Question

a submarine below 608 m below sea level sends a sonar signal detect an sircraft directly above it. if it receive signal 10 sec later how far is aircraft from submarine

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Answer 1

Answer:

2253.8 m

Step-by-step explanation:

Let the distance from the surface of the water to the aircraft is d

The sound goes from water to air and comes back to the submarine after 10 seconds

Therefore, in 5 seconds, the distance travelled by the sonar signal = (d+608) m

Taking speed of sound in water = 1450 m/s

And speed of sound in air 332 m/s

we get

5 = time taked by the signal in air + time taken in water

$\implies 5 = \frac{608}{1450} + \frac{d}{330}$

$\implies\frac{608}{145} + \frac{d}{33} =50$

$\implies 4.19 + \frac{d}{33} =50$

$\implies \frac{d}{33} =45.80$

$\implies d =45.80\times 33$

$\implies d =1645.80\text{m}$

Therefore the distance of aircraft from submarine = (608 + 1645.8) m

                                                                                   = 2253.8 m

Hope this helps.