Question

A submarine emits a sonar pulse which returns from an underwater cliff in 1.02 seconds. if the speed of sound in salt water is q531 m/s, how far is the cliff?

Answer 1

total distance = speed * time
in this case, we need one way distance,
so, distance = speed * time / 2
                       = 1.02 * 1531 / 2
                       = 1561.62 / 2
                       =  780.81 meters 

Answer 2

Answer:

2d=v×t

2d=1531×1.02

d=1561.63÷2

d=780.81 metre