Question

a submarine emits sonar pulse,which returns form an underwater cliff in1.02sec.if the speed of sound in salt water is 1531m/ sec how far away is the cliff

Answer 1

Given: Speed of sound in water = 1531 m/s
Time taken = 1.02 sec
Distance between submarine and cliff is
$d = \frac{vt}{2} \\ \: \: \: \: = \frac{1531 \times 1.02}{2} \\ \: \: \: \: = \: 780.81 \: m$

Answer 2

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Time taken by the sonar pulse to return, t = 1.02 s

Speed of sound in salt water, v = 1531 m s−1

Distance of the cliff from the submarine = Speed of sound × Time taken

Distance of the cliff from the submarine = 1.02 x 1531 = 1561.62m

Distance travelled by the sonar pulse during its transmission and reception in water = 2 × Actual distance = 2d

Actual Distance , d = (Distance of the cliff from the submarine)/2 = 1561.62/2 = 780.31 m

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