A submarine was initially anchored
3,000 m below sea level. After a few days, it
moved up 3 by 5 of the distance below sea level.
At what level is the submarine now? (Hint:
Depth below sea level is negative.)
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2
Answer:
-1200 m
Step-by-step explanation:
- (P1) Initial position of the submarine= - 3000m
- (P2) Position of submarine moved up after few few days=3/5
- Final position of the submarine= P2×P1
= 3/5 ×3000
= 3×600
= 1800m
Final position= Initial position-position of submarine moved up by
= - 3000 + 1800
= - 1200m
Ans:- The submarine is at 1200m below level now.
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