Math, asked by Infinite8968, 9 months ago

A submarine was sailing at 1200 ft below sea level. We can express this vertical position as −1200 ft. Now, the submarine starts ascending at a constant rates of 50ft/min.what will be its vertical position after 5 minutes.after ascending for some time,it is now at 500 ft below sea level.what was it’s vertical position six minutes ago.

Answers

Answered by shreeya5810
7

Answer:

Step-by-step explanation:-

After five minutes it's position of submarine is

1min=50km

In 5min= 50×5= 250km

Position of submarine = -1200+205= -995km

If position of submarine = -500

So the position of the submarine 6min ago will be :-

1min=50km

6min=6×50=300km

Position of submarine=-500-300= -800km

Answered by 86617
2

Answer:

-800

Step-by-step explanation:

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