Question

18g of glucose is present in 500zm³ of its aqueous solution . What is the molarity of the solution ? What additional data is required if the molality of the solution is required to be calculated

Answer 1

$\bf \fbox{GIVEN} \downarrow$

$\bf Mass \:of\: glucose\:=18 g$

$\bf Volume \:of\: aqueous \: solution=500 m³$

$\bf \fbox{To Find} \downarrow$

$\bf {Molarity}$=?

Molar mass of Glucose =180 g

$molarity = \frac{ \frac{18}{180} }{ \frac{500}{1000} } \\ \\ = \frac{2}{10} \\ \\ = 0.2$

$\bf {Molarity}$=0.2M

$\bf \fbox{additional\: data \:for \:molality\: is density}$

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