Question

A subset B n(A)=5,n(B)=8 then find n(A intersection B)​

Answer 1

Given A⊂B, n(A)=5 and n(B)=7

Since, A⊂B⇒ all the elements of set A are also present in set B ⇒n(A∩B)=5

Since, n(A∪B)=n(A)+n(B)−n(A∩B)

⇒n(A∪B)=5+7−5

⇒n(A∪B)=7

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Answer 2

Answer:

Given A⊂B, n(A)=5 and n(B)=7

Since, A⊂B⇒ all the elements of set A are also present in set B ⇒n(A∩B)=5

Since, n(A∪B)=n(A)+n(B)−n(A∩B)

⇒n(A∪B)=5+7−5

⇒n(A∪B)=7