Question

a sum amount to RS 2400 at 6% simple interest per annum after 1 1/2 years . find sum​

Answer 1

We must remember

if the sum is P, time is t years, rate of simple interest is r% per year and the interest gained is I, then we relate the variables by

$\quad\quad I=\frac{Ptr}{100}$

Given data:

Here amount = sum + interest

If P be the sum and I be the interest, then

interest, $I = Rs. (2400 - P)$

rate of simple interest, $r=6\%$ p.a.

time, $t=1\frac{1}{2}\:years=\frac{3}{2}\:years$

Step-by-step explanation:

Using the formula $I=\frac{Ptr}{100}$, we get

$\quad 2400-P=\frac{P\times \frac{3}{2}\times 6}{100}$

$\Rightarrow 2400-P=\frac{9}{100}P$

$\Rightarrow P+\frac{9}{100}P=2400$

$\Rightarrow \frac{109}{100}P=2400$

$\Rightarrow P=2400\times\frac{100}{109}$

$\Rightarrow P=2201.83$

Answer:

The required sum is Rs. 2201.83.

Answer 2

Step-by-step explanation:

see the attached image above....

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