A sum lent at compound interest amounted to
18700 at the end of 3 years and to 20570 at the
end of 6 years. Find the sum (in rs).
Answers
Answered by
0
Answer:
17000
Step-by-step explanation:
20570 = s(1+ r/100)^6
18700 s(1+ r/100)^3
---------- = ---------------------
20570 s(1+ r/100)^6
1870/2057 = (1+r/100)^(-3)
10/11 = (1+r/100)^(-3)
11/10 = (1 + r/100)^(3)
11/10 = [(100 + r)/100]^(3)
11/10 = (100 + r)^3 /100*100*100
1100000 = (100 + r)^3
(100 + r) = (1100000)^(1/3)
(100+r) = 103.23
r = 3.23 %
18700 = s(1+3.23/100)^3
18700 = s(1+0.0323)^3
s = (18700)/1.1
= 17000 approx
Answered by
0
Answer:
17,000 rs
Step-by-step explanation:
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