Math, asked by TbiaSupreme, 1 year ago

A sum of ₹1000 is invested at 8% simple interest per year. Calculate the interest at the end of each year. Do these interests form an AP? If so, find the interest at the end of 30 years.

Answers

Answered by harshitgaourav8
12

given,

   principal=1000

    rate of interest=8%

      number of years=1 year

     SI=Pnr/100=1000x1x8/100=rs.80

when n=2 years,SI=1000x2x8/100=rs.160

when n=3years,SI=1000x3x8/100=rs.240

the sequence is 

    80,160,240,..........

this is in AP as a,first term=80,d,common difference=80

interest at the end of 30 years,t30=a+(n-1)d

                                                =80+(30-1)80

                                                =80+29(80)

                                                =80+2320

                                                =2400


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