Question

A sum of 2580 is divided among A B and C such that A's part of sum is half of B's part and B's part is 2/3 of C's part. How much will B get?​

Answer 1

Answer:

B=860

Step-by-step explanation:

A+B+C=2580

A=1/2(B)

B=2/3(C) => C=3/2(B)

1/2(B) + B +  3/2(B)=2580

3B=2580

B=860

Answer 2

Step-by-step explanation:

let C get x

then B get 2/3x

A get 1/2 ×2/3 x= 2/6x = 1/3x

therefore x +2/3x +1/3x = 2580

3x + 2x + x / 3= 2580

6x/3=2580

2x =2580

x = 2580/2 = 1290

therefore C get 1290

B get 2/3× 1290 = 2×430 = 860