Math, asked by shrivastavaaditya846, 10 months ago

A sum of 3000 is to be given in the form of 63 prizes.If a prize is of either 100 and 25 .find the number of prizes of each type?​

Answers

Answered by TheLostMonk
1

Answer:

19,44

Step-by-step explanation:

25x + (63 - x)×100 = 3000

25x + 6300 - 100x = 3000

75x = 3300 => x = 44

no. of Rs 25 prizes = x = 44

no. of Rs 100 prizes = 63 - 44 = 19

Answered by Anonymous
1

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Given the sum of prizes money = 3000

➡ Total number of prizes = 63

➡ number of prizes cost = 100x

➡ number of prize of cost = 25

will be 63 - x

From the problem we can write

=> x × 100 (63 - x) 25 = 3000

=> 100x + 1575 - 25x = 3000

(transporting) 1575 on L.H.S to R.S.H

we get

=> 100x - 25x = 3000 - 1575

=> 75x = 1425

=> x = 1425÷ 75

=> x = 19

number of 100 prizes = 19

number of 25 prizes = 63 - 19

➡ answer = 44

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