A sum of 3000 is to be given in the form of 63 prizes. If the Prize money is either 100 or 25 . Find the number of prizes of each type
Answers
Total sum is 3000 rupees
Total no of prizes is 63
Then x+y=63 (equation 1)
100x+25y=3000 (equation2)
By simplifying 2 equation we get
4x+y=120. (equation 3)
Subtract equation 1 from equation 3
4x+y-x-y=120-63
3x=57
x=19
put x=19 in equation 1
19+y=63
y=63-19=44
No of prizes of rs 100 =19
No of prizes of rs 25= 44
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Answer:
100rs prizes = 19
25rs prizes. = 44
Step-by-step explanation:
Let the number of prizes of cost 100rs be x
The number of prizes of cost 25 rs be y
By the sum
= x + y = 63
= y = 63 - x
= 100x + 25y = 3000
= 4x + y = 120
= y = 120 - 4x
= 63 - x = 120 - 4x
= 4x - x = 120 - 63
= 3x = 57
= x = 57/3
= x = 19
= y = 63 - x = 63 - 19
= 44
The no.of prizes of cost 100rs = 19
The no.of prizes of cost 25 rs = 44