A sum of ₹ 3000 yields an interest of ₹ 1080 at 12% per annum simple interest in how many years ?
Answers
Answered by
6
hey
______________________________
Time = 100×SI/P×R
S.I. = ₹1080
P = ₹3000
R = 12% p.a.
♦ Time
= 100×1080/3000×12 years
= 108000/36000 years
= 3 years
♢ Time is 3 years
______________________________
[ you can also find it by equation ]
Let the time be x years
A.T.Q.
S.I. = P×R×T
=> 1080 = 3000×12×x/100
=> 108000 = 36000x
=> 108000/36000 = x
=> 3 = x
♢ Time = x years = 3 years
______________________________
I hope this answer helps you....♡
Plz mark my answer BRAINLIEST....
Need any furthur help, plz contact....
#Amitavo1
______________________________
Time = 100×SI/P×R
S.I. = ₹1080
P = ₹3000
R = 12% p.a.
♦ Time
= 100×1080/3000×12 years
= 108000/36000 years
= 3 years
♢ Time is 3 years
______________________________
[ you can also find it by equation ]
Let the time be x years
A.T.Q.
S.I. = P×R×T
=> 1080 = 3000×12×x/100
=> 108000 = 36000x
=> 108000/36000 = x
=> 3 = x
♢ Time = x years = 3 years
______________________________
I hope this answer helps you....♡
Plz mark my answer BRAINLIEST....
Need any furthur help, plz contact....
#Amitavo1
Answered by
2
Answer:
3 yrs
Step-by-step explanation:
given...
Principal=Rs3000
Rate=12%
SI=Rs1080
.
.
.
.
.
.
.
Time =
Hence, Time =3yrs
Thank you
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