Question

A sum of ₹ 3000 yields an interest of ₹ 1080 at 12% per annum simple interest in how many years ?

Answer 1

hey
______________________________

Time = 100×SI/P×R

S.I. = ₹1080
P = ₹3000
R = 12% p.a.

♦ Time
= 100×1080/3000×12 years
= 108000/36000 years
= 3 years

♢ Time is 3 years
______________________________

[ you can also find it by equation ]

Let the time be x years

A.T.Q.

S.I. = P×R×T

=> 1080 = 3000×12×x/100
=> 108000 = 36000x
=> 108000/36000 = x
=> 3 = x

♢ Time = x years = 3 years
______________________________

I hope this answer helps you....♡

Plz mark my answer BRAINLIEST....

Need any furthur help, plz contact....

#Amitavo1

Answer 2

Answer:

3 yrs

Step-by-step explanation:

given...

Principal=Rs3000

Rate=12%

SI=Rs1080

.

.

.

.

.

.

.

Time =

$si \times100 \div p \times r$

$1080 \times 100 \div 3000 \times 12$

Hence, Time =3yrs

Thank you