Question

A sum of ₹3500 amounts to ₹4064 years at a certain rate of interest in what time will ₹6000 amount to ₹7200 at a same rate of interest?​

Answer 1

Step-by-step explanation:

Given, P= Rs. 6000, Amount = Rs. 7200, Time =4 years

S.I. =A−P= Rs. 7200− Rs. 6000

S.I = Rs. 1200

∴ Rate =(

6000×4

1200×100

)%p.a.=5%p.a.

New rate =1.5×5=7.5%p.a.

∴ Required amount = Rs. 6000+ Rs.

100

6000×7.5×5

= Rs. 6000+ Rs. 2250

= Rs. 8250

I hope this answer is helpful for you

Answer 2

Answer:

Given:

Amount = Rs. 7200

Principal = Rs. 6,000

Time = 4 years

Formula Used:

Amount = Principal + Interest

Simple interest = (Principal × Time × Rate of interest)/100

Calculation:

Simple interest = Amount - Principal

⇒ Simple interest = Rs. 7200 - Rs. 6000

⇒ Simple interest = Rs. 1200

Simple interest = (Principal × Time × Rate of interest)/100

⇒ 1200 = (6000 × 4 × Rate of interset)/100

Rate of interest = 5% p.a.

Now,

Increase rate of interest = 5%p.a. + 2% p.a. = 7% p.a

Time = 5 years

⇒ Simple interest = (6000 × 5 × 7)/100

⇒ Simple interest = 2100

Amount = Principal + Simple interest

⇒ Amount = Rs. 6000 + Rs. 2100 = Rs. 8100

Step-by-step explanation:

hope it's helps you.