a sum of ₹800 is in the forms of denominations of 10₹ and 20₹ if the total number of notes is 50 find the number of notes of each type
Answers
Hey User !
=) Let there be X notes of Rs 10.
Total number of notes = 50.
∴ Number of notes of Rs 20 = (50 – x)
Total sum of money = Rs 800
∴ 10x+ 20 (50 – x) = 800
⇒ 10x+ 1000 – 20x = 800
⇒– 10x = 800 – 1000
⇒ – 10x= – 200
⇒x= 20
∴ 50 – x = 50 – 20= 30
So, there are 20 notes of Rs 10 and 30 notes of Rs 20.
Hope , It Helps ...
Answer:
Step-by-step explanation:
So here you are with answer
Given:
Total money = ₹800
Money in denominations = ₹10,₹20
Total number of notes = 50
Solution:
Let 'x' be the number of ₹10 notes
Let (50-x) be the number of ₹20 notes
Value of ₹10 notes = 10*x = 10x
Value of ₹20 notes = 20(50-x)
No. Of notes of each type
10x + 20(50-x)= 800
10x + 1000-20x=800
10x-20x=800-1000
-10x = -200
x = 200/10
x = 20
Therefore ,
Number of ₹10 notes = 20
Number of ₹20 notes = [50-20]=30