Math, asked by lbasanta273, 3 months ago

A sum of money a boy spends 1/3 and then 1/6 of remaining.He had Rs.25 the total amount was​

Answers

Answered by sb93
0

Answer:

Sum = ₹450

Step-by-step explanation:

Solution:

Let the sum be 100,

So, Boy spends 1/3rd of 100:

\implies \sf{{\Large\frac{1  }{ 3 }} × 100 }

\implies \sf{{\Large\frac{100  }{ 3 }} }

Next, he spends 1/6th of remaining:

\implies \sf{{\Large\frac{1  }{ 6 }}×{\Large\frac{ 100 }{  3}} }

\therefore \sf{{\Large\frac{ 50 }{ 9 }} }

Using unitary method:

if the remaining is ₹50/9, then the sum is ₹100

if the remaining is ₹25, then the sum is ?

\implies \sf{ {\Large\frac{50  }{ 9 }}× Sum = 25 × 100}

\implies \sf{sum ={\Large\frac{2500×9  }{  50}}  }

\therefore \boxed{\sf{ Sum = ₹450 }}

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