A sum of money amounts to rs.2880 in 2 years and 3456 in 3 years at compound interest. find the sum.
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Given that a Sum (Principal amount) amounts to 28880(compounded amount) in 2 years (time)
so P=Principal amount.. C=Compounded amount..N or T = Time.
we know that Compounded Amount= P(1+i)^n - 1)
2888=P(1+i)^2 ......(1)
Also that same sum (Principal amount) amounts to 3456(compounded amount) in 3 years (time)
3456 = P(1+i)^3 ........(2)
Now (2)÷(1)
3456/2888 =P(1+i)^3/P(1+i)^2
12 = (1+i)
12-1 = i ...
therefore i=Rate of interest Per annum=11%
so P=Principal amount.. C=Compounded amount..N or T = Time.
we know that Compounded Amount= P(1+i)^n - 1)
2888=P(1+i)^2 ......(1)
Also that same sum (Principal amount) amounts to 3456(compounded amount) in 3 years (time)
3456 = P(1+i)^3 ........(2)
Now (2)÷(1)
3456/2888 =P(1+i)^3/P(1+i)^2
12 = (1+i)
12-1 = i ...
therefore i=Rate of interest Per annum=11%
Answered by
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Answer:
Explanation: 3456-2880==576
Rate === 576/2880×100==20%
Sum == 5 6
5 6
5 6
== 3456/216×125===2000
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