Question

Two fair dice are thrown. what is the probability of the sum of 10 being obtained for the two uppermost faces ?

Answer 1

2 Dice r thrown

so total no of events = 6 sq =36

for sum of 10

then sample space ={5,5},{6,4}{4,6}

ie sample space of sum of 10=3

Now probability P(E)=3/36

=1/12 Ans

Hope it helps u friend!

Answer 2

The probability of getting the numbers that sum up to 1/12.

GIVEN: Two fair dice are thrown.

TO FIND The probability of the sum of 10 being obtained for the two uppermost faces.

SOLUTION:

As we are given in the question,

2 dice are thrown.

So the total possible outcomes will be 36.

The sample space for both numbers summing up to 10 will be.

{5,5},{6,4}{4,6}

Therefore,

Possible outcomes for numbers coming to that sum up to 10 =3

Therefore,

The required probability = 3/36

The required probability = 1/12

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