A sum of money at compound interest amount to rs 3920 in 1 year and 4390.4 in 2 year find the principal
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Let Principal be P
Formula of compound interest,
Amount = P [ 1 + r /100 ] ^ n
r : rate of interest
n : time in years
For 1 Year,
3920 = P [ 1 + r / 100 ] ¹
[ 1 + r /100 ] = 3920 / P ........(1)
For 2 Years,
4390.4 = P [ 1 + r /100 ] ²......(2)
From (1) and (2)
4390.4 = P ( 3920 / P ) ²
4390.4 = P ( 15366400 ) ÷ P²
4390.4 = 15366400 ÷ P
P = 15366400 ÷ 4390.4
P = 3500
Formula of compound interest,
Amount = P [ 1 + r /100 ] ^ n
r : rate of interest
n : time in years
For 1 Year,
3920 = P [ 1 + r / 100 ] ¹
[ 1 + r /100 ] = 3920 / P ........(1)
For 2 Years,
4390.4 = P [ 1 + r /100 ] ²......(2)
From (1) and (2)
4390.4 = P ( 3920 / P ) ²
4390.4 = P ( 15366400 ) ÷ P²
4390.4 = 15366400 ÷ P
P = 15366400 ÷ 4390.4
P = 3500
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