Question

A sum of money at simple interest doubles itself in 8 years 4 months. In how much time
will it triple itself?

Urgently answer
Fast

With Explanation

If R=12
(For reference)

Answer 1

let principal amount = 100
internet = 100
according to formula
100 = (100 * 25/3 * R)/100
R = 12%
now interest = 200
200 = 100 *12 *t / 100
t = 200/12 = 16.66 = 16 year 8 months

Answer 2

Hi friends

Here is your answer

Let Sum is p
Amount = 2p

SI = A - P
= 2P - P
= P

T = 8 years 4 month
= 8+4/12
= 8+1/3
= 25/3 years

As we know
R = SI × 100/P×T
$= \frac{p \times 100 \times 3}{p \times 25} \\ \\ = 4 \times 3 \\ \\ = 12 \%$
Now
A = 3p
SI = 3P - P
= 2P

As we know
Time = SI × 100/P×R
$= \frac{2p \times 100}{p \times 12} \\ \\ = \frac{50}{3} \\ \\ = 16 \frac{2}{3} \\ \\ = 16 \: years \: \frac{2}{3} \times 12 \: months \\ \\ = 16 \: years \: 8 \: months$
Therefore Amount will triple itself in 16 years and 8 months.

Hope it helps you

@ MSD