Question

A sum of money becomes double in 10 years at a certain rate of interest find the rate of interest

Answer 1

Step-by-step explanation:

Principal =x rupees

AMOUNT = 2x rupees

S.I=A-P=p rupees

Time = 10 years

Rate of interest=100×S.I/P×T

=100×P/P×10

10%p.a.

Answer 2

Answer:

Step-by-step explanation:

Let principle be x

Amount = 2x

T= 10 years

SI = A-P = 2x-x = x

R = (SI x100) / (P x T)

= (X × 100) / (X × 10 )

= 10%