Math, asked by swatisingh9095, 6 months ago

A sum of money double itself in 10 years. find the rate of interest

Answers

Answered by Anonymous
3

Answer:

Step-by-step Let the principal be x

Time = 10 years

Amount after 10 years gets doubled

So amount = 2x

simple interest = amount - principal

simple interest = 2x - x = x

Rate per annum = SI × 100 / P × T

= x × 100 / x × 10

100x/ 10x = 10

So rate per annum = 10%.

Hope my answer helps you

Answered by Anonymous
14

 \bf \bigstar \pink Q \pink UE STION

A sum of money double itself in 10 years. find the rate of interest.......

 \bf \star \huge\pink a \pink nswer

Let the principal be =x

Then,in 2 years the amount will be- x×2=2x

Now,interest= amount - principal=2x - x = 1x

Time= 10 year

Rate=?

Now, RATE= interest/principal×100/time

So, R=1X/X × 100/10

 \bf \pink \R= \pink1 \pink0% }bf  \pink \}

Similar questions