A sum of money doubles itself in 20 yrs, in how many years would it treble itself?
Answers
Answer:
30 years.
Step-by-step explanation:
Supposed,, we have 100 taka. it will 200 after 20 years.. now we have 200 and it will 300 after 30 years.
Question :
A sum of money doubles itself in 20 yrs, in how many years would it treble itself?
Answer :
In 40years, the sum of money would treble itself.
Given :
Time taken by the Principal amount to double itself = 20years
To find :
No.of years when the principal amount would treble itself
Solution :
Let the Principal be Rs.P
According to the problem ,
Amount (A) = 2P
Time (T) = 20 years
We know,
Simple interest (SI) = A - P
= 2P - P
= P
We also know ,
SI = PRT / 100
Rate of interest (R) is not known
Therefore, P = (P×R×20)/100
=> P = 20 PR /100
=> 100 P = 20 PR
=> 100P/P = 20 R
=> 100 = 20R
Hence, R = 100/20
= 5% p.a
Hence,
When Principal = P , R = 5 % p.a ,
Amount = 3P
SI = 3P - P
= 2P
According to the problem,
2P = P×5×T/100
=> 2P/P = 5T/100
=> 2 × 100 = 5T
=> 200 = 5T
Or, T = 200/5
T = 40
Hence, in 40years, the sum of money would treble itself.
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