A sum of money doubles itself in 3 year at a simple interest in how many year will it amount to 8 times it self
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p×r×t/100 +p = 2p
p×r×t/100 = p
r×8 = 100
r = 12.5 %
so to become 8 times
p×r×t/100 +p = 8p
p×12.5×t/100 = 7p
12.5t =7×100/12.5 = 700/12.5 = 56 years
p×r×t/100 = p
r×8 = 100
r = 12.5 %
so to become 8 times
p×r×t/100 +p = 8p
p×12.5×t/100 = 7p
12.5t =7×100/12.5 = 700/12.5 = 56 years
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