Question

A sum of money invested at a certain rate doubles itself in 10years. How much time will it take to triple itself at the same rate?

Answer 1

Answer:

Let Principle amount P = ₹ 100,

After 10 years amount will be A = ₹ 200,

It means we get an interest  I = ₹ 100

Now We want our amount would be A = ₹ 300,

Years for I of ₹ 100 = 10 years

∴ Years for I of ₹ 200 = (10/100) × 200

                                 = 20 Years

∴ It will take 20 Years to triple the amount

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Let simple interest=s

principal=p

Amount=a

rate of interest=r

Time=t

S=ptr/100=p*10*r/100=pr/10

A=p+s

Given A=2p

2p=p+pr/10

2p-p=pr/10

p=pr/10

r=10

If it triples itself in ?

Now S=p*t*r/100

s=p*t*10/100

s=pt/10

A=3p( given)

3p=p+pt/10

2p=pt/10

t=20 years