Question

A sum of money invested on simple interest amounts to 620 in 3 years and to 690 in 5 years. The sum invested is:
(A) 550
(B 410
(C) ₹585
(D ₹515​

Answer 1

Answer:

550

Step-by-step explanation:

cause solve it bruh use brain not brainly

Answer 2

Given:

A sum of money invested on simple interest amounts,

620 in 3 years and

690 in 5 years

To find :

The sum invested.

Formula to be used:

$A_{n}$ = P + ( n × I)

Solution:

Step 1 of 2:

Let , $A_{3}$ = 620

$A_{5}$ = 690

Substituting the values in the following formula,

$A_{n}$ = P + ( n × I )

$A_{3}$ =  P + ( 3 × I )

620 = P + 3I         ------------- Eq (1)

$A_{5}$ =   P + ( 5 × I )

690 = P + 5I        ------------- Eq (2)

Subtracting Eq (2) from Eq (1) we get ,

690 - 620 =  P + 5I  - P - 3I  

70 = 2I

I = $\frac{70}{2}$

I = 35

Step 2 of 2:

Substitute  I = 35 in Eq(1)

620 = P + 3I

620 = P + 3(35)

620 = P + 105

620 - 105 = P

P = ₹515​

Final answer:

Therefore, the sum invested is ₹515​.

Thus, the correct option is (D) ₹515​