A sum of money is borrowed and paid back in two equal annual installments of 882, allowing 5% compound interest. the sum borrowed was
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Answered by
27
"The general formulae for installments in case of compound interest is P =x/(1+r/100) + x/(1+r/100)^2 ....x/(1+000)
And here we have to find P
Given x = 882 r = 5 and n=2
On substituting the values
We get P =882/ (1+5/100) + 882/ (1+5/100) ^2 p = 882*20/21 + 882*400/441
P= 840 + 800 = 1640
"
Answered by
32
⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟
➧ Compound interest is:
➧ P = x / (1 +r / 100) +
x / (1 + r / 100)²
x / (1 + r / 100)ⁿ
➧ Here, we have to find P given:
➾ x = 882
➾ r = 5
➾ n = 2
➧ On substituting the values we get:
➧ P = 882 / (1 + 5 / 100) +
882 / (1 + 5 / 100)²
➧ p = 882 × 20 / 21 +
882 × 400 / 441
➾ P = 840 + 800
➾ p = 1640 ...✔
_________
Thanks...✊
▬▬▬▬▬▬▬▬▬▬▬▬☟
➧ Compound interest is:
➧ P = x / (1 +r / 100) +
x / (1 + r / 100)²
x / (1 + r / 100)ⁿ
➧ Here, we have to find P given:
➾ x = 882
➾ r = 5
➾ n = 2
➧ On substituting the values we get:
➧ P = 882 / (1 + 5 / 100) +
882 / (1 + 5 / 100)²
➧ p = 882 × 20 / 21 +
882 × 400 / 441
➾ P = 840 + 800
➾ p = 1640 ...✔
_________
Thanks...✊
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