A sum of money is distributed between A and B. A got 60%of all the money and B got Rs 1170 less than A.how much money is distributed between A and B.
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Answered by
10
Let the sum be 's'
A --> 60% of s = 60/100 x s
B got 1170 less than 60s/100
i.e 6s/10 - 1170
But A + B = s
6s/10 + 6s/10 - 1170 = s
12s/10 - 1170 = s
12s/10 - s = 1170
2s/10 = 1170
s/5 = 1170
s = 5850
A --> 60/100 x 5850 = Rs 3510
B --> 3510 - 1170 = Rs 2340
Hope This Helps You!
A --> 60% of s = 60/100 x s
B got 1170 less than 60s/100
i.e 6s/10 - 1170
But A + B = s
6s/10 + 6s/10 - 1170 = s
12s/10 - 1170 = s
12s/10 - s = 1170
2s/10 = 1170
s/5 = 1170
s = 5850
A --> 60/100 x 5850 = Rs 3510
B --> 3510 - 1170 = Rs 2340
Hope This Helps You!
himamoto:
thanku
Answered by
4
Let all money be Rsx
A got 60% means Rs60x/100
B got 1170 less than A means Rs60x/100-1170
so
60x/100+60x/100-1170=x
120x/100=x+1170
120x=100x+117000
20x=117000
x=5850
so total money is Rs 5850
A got 60/100×5850=Rs4130
B got 4130-1170=Rs2960
A got 60% means Rs60x/100
B got 1170 less than A means Rs60x/100-1170
so
60x/100+60x/100-1170=x
120x/100=x+1170
120x=100x+117000
20x=117000
x=5850
so total money is Rs 5850
A got 60/100×5850=Rs4130
B got 4130-1170=Rs2960
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