Math, asked by viduola, 1 year ago

A sum of money is distributed between A and B. A got 60%of all the money and B got Rs 1170 less than A.how much money is distributed between A and B.

Answers

Answered by Fuschia
10
Let the sum be 's'

A --> 60% of s = 60/100 x s

B got 1170 less than 60s/100

i.e 6s/10 - 1170

But A + B = s
6s/10 + 6s/10 - 1170 = s
12s/10 - 1170 = s
12s/10 - s = 1170
2s/10 = 1170
s/5 = 1170
s = 5850

A --> 60/100 x 5850 = Rs 3510
B --> 3510 - 1170 = Rs 2340

Hope This Helps You!

himamoto: thanku
viduola: thanks
Sarth45: i noticed a mistake can i tell
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Answered by Sarth45
4
Let all money be Rsx

A got 60% means Rs60x/100

B got 1170 less than A means Rs60x/100-1170

so

60x/100+60x/100-1170=x

120x/100=x+1170

120x=100x+117000

20x=117000

x=5850

so total money is Rs 5850

A got 60/100×5850=Rs4130

B got 4130-1170=Rs2960

himamoto: yes you're right
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