A sum of money is divided among three persons. X, Y and Z, in the ratio 10 : 7:5. If y gets Rs. 140 more than Z, how much will X get?
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A small correction in your Question.
Correct Question :
A sum of money is divided among three persons. X, Y and Z in the ratio 10 : 7 : 5. If Y gets Rs. 14 more than Z, how much will X get ?
Solution :
Let the unknown money (amount's value) be 'a'
The Ratio will be 10a : 7a : 5a
We know that,
X : Y : Z = 10a : 7a : 5a
Hence,
- X = 10a ------- (1)
- Y = 7a -------- (2)
- Z = 5a -------- (3)
According to the question :
It is given that, Y gets 14 more than Z, which can be written as,
→ Y = 14 + Z
(Substitute Y & Z's value from (2) & (3))
→ 7a = 14 + 5a
→ 14 = 7a - 5a
→ 14 = 2a
→ 2a = 14
→ a = 14 / 2
→ a = 7
Substituting 'a' value in (1), (2) & (3) :
→ X = 10a = 10 × 7 = 70
→ Y = 7a = 7 × 7 = 49
→ Z = 5a = 5 × 7 = 35
Hence, X gets ₹70, Y gets ₹49 and Z gets ₹35.
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