Question

a sum of money is lent at 8% per annum compound interest if the interest for the second year exceeds for the first year by rupees 96 find the sum of money​

Answer 1

Answer:

For 1st year p=rupees x .Rate=8% Time =1year

interest =x*8*1/100

=0.08x

and amount =x+0.08x=1.08x

For 2nd year P=1.08x rupees Rate=8% Time= 1 year

Interest =1.08x*8*1/100

=0.0864x

Amount =1.08x+0.0864x

=1.8864 x

0.0864x-0.08x=96

x=15000

Step-by-step explanation:

Follow me

Answer 2

Answer:

Sum of money is 15000

Step-by-step explanation:

Given Problem:

A sum of money is lent at 8% per annum compound interest if the interest for the second year exceeds for the first year by rupees 96 find the sum of money​.

Solution:

To Find:

Sum of money

--------

Method:

For 1st year p =rupees x .

Rate = 8%

Time =1 year

Interest = $\frac{x*8*1}{100}$

=0.08x

and amount =x+0.08x=1.08x

For 2nd year P=1.08x

Rupees Rate=8% Time= 1 year

Interest =1.08x*8*1/100

=0.0864x

Amount =1.08x+0.0864x

=1.8864 x

0.0864x-0.08x=96

x = 15000...............(answer)