Math, asked by khushi44845, 10 months ago

A sum of money is to be distributed among A, B,
C and D in proportion 9:7: 13 : 5. If C gets
2400 more than D, then the sum of shares of B
and C is
(1) 3000
(2) 4000
(3) 5000
(4) 6000

Answers

Answered by omprakashmalviya2000
8

Answer:

(3) 5000

Step-by-step explanation:

Let the money got to A, B, C and D be 9x, 7x, 13x and

5x respectively.

Difference between the shares of C and D: 2400

13x - 5x = 2400

→8x = 2400

{Transposing 8 to RHS}

→x = 2400/8

→x = 300

Share of A: 9x → 9×300 → 2700

Share of B: 7x → 7×300 → 2100

Share of C: 13x → 13×300 → 3900

Share of D: 5x → 5×300 → 1500

Sum of shares of B and C → 2100 + 3900

→ 5000

Hence, answer is (3) 5000.

Answered by Anmolpreet127
5

Answer:

4)6000

Step-by-step explanation:

Let their shares be 9x,7x,13x,5x.

shares of c-shares of d=2400(given)

13x-5x=2400

8x=2400

x=2400/8

x=300

Shares of A=9*300=2700

Shares of B=7*300=2100

Shares of C=13*300=3900

Shares of D=5*300=1500

Sum of shares of B and C=2100+3900

                                           =6000

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