Question

Find the area of a triangular field of whose side are 50 m, 45 m and 35 m​

Answer 1

Step-by-step explanation:

using heron's formula,

$s = \frac{50 + 45 + 35}{2 } = \frac{130}{2} = 65 \\ \\ a = 50 \: \: \: \: b = 45 \: \: \: \: c = 35 \\ \\ = \sqrt{s |s - a| \: |s - b| \: \: |s - c| } \\ = \sqrt{65 |65 - 50| \: \: |65 - 45| \: \: |65 - 35| } \\ = \sqrt{65 |15| \: |20| \: |30| } \\ = \sqrt{13 \times5 \ \times 15 \times 4 \times 5 \times 2 \times 15} \\ = 5 \times 2 \times 15 \sqrt{13 \times 2} \\ = 150 \sqrt{26 } {m}^{2}$