Math, asked by bindutiwari, 1 year ago

a sum of money lent out at simple interest amount to rs 2200in one year and rs2800in 4years. find the sum of money and the rate of interest

Answers

Answered by ankitrishab
0
Let principal be x Case 1: P=x  A=2200, T=1 year, I=2200-x Rate=(2200-x)100/xCase 2: P=x  A=2800  T=4 years I=2800-xRate=(2800-x)100/4x Since rate is same in both cases, we equate the two equations (2200-x)100/x=(2800-x)100/4xx=2000 therefore Rate=(2200-2000)100/2000       =10%
Answered by rosangiri28pfbc5r
0
Let Sum= P lent out
After 1 year , rs 2200= P (1+r/100)........ (i)
After 4 years, rs 2800= P (1+4r/100)..... (ii)
Substract (i) from (ii)

or, 2800-2200= 3Pr/100
or, 600= 3Pr/100
or, 3Pr= 60000
or, Pr= 20000...... (A)
Substitute Pr in (i)

2200= P+200
or, P= 2000
Now
from (A)
Pr=20000
2000×r= 20000
r= 10
Hence ,sum of money and rate of interest are 2000 and 10 respectively

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