Question

a sum of money put at 11% per annum, SI amounts to 10370 in 2 yrs. What will it amount to in 3 yrs at the same rate??? ​

Answer 1

✬ Amount = Rs 11305 ✬

Step-by-step explanation:

Given:

• Rate is 11 % per annum.
• Amount is Rs 10370.
• Time is 2 years.

To Find:

• What is the principal and what will be amount after 3 years?

Solution: Let the principal be Rs p.

As we know that formula for S.I is

★ S.I = P $\times$ R $\times$ T/100 ★

Put the values on formula

$\implies{\rm }$ S.I = (P $\times$ 11 $\times$ 2/100)

$\implies{\rm }$ S.I = (11P/50)

So, the Simple Interest is Rs 11P/50.

Now using

★ Amount = Principal + Interest ★

➯ 10370 = (P + 11P/50)

➯ 10370 = (50P + 11P/50)

➯ 10370 $\times$ 50 = 61P

➯ 518500 = 61P

➯ 518500/61 = P

➯ Rs 8500 = Principal

∴ Amount after again 3 years of S.I with principal 8500 will be

$\implies{\rm }$ S.I = (8500 $\times$ 11 $\times$ 3/100)

$\implies{\rm }$ S.I = (85 $\times$ 33)

$\implies{\rm }$ S.I = Rs 2805

Therefore, Amount after 3 years will be

➟ Amount = 8500 + 2805

➟ Amount = Rs 11305

Hence, the amount after 3 years will be Rs 11305

Answer 2

GIVEN :-

• Rate = 11%

• Amount = Rs.10370

•Time = 2 years

TO FIND :-

• The amount after 3 years.

SOLUTION :-

We know that,

$\dagger \: { \boxed { \red{ \tt{S.I = \frac{ P × R × T }{100} }}}}$

[ Put the values ]

$\longrightarrow \: \tt \: S.I \: = \: \frac{P \: \times 11 \times \cancel2}{ \cancel{100}} \\ \\ \longrightarrow \: \: \tt { \green{\: S.I \: = \: \frac{11P}{50}}} \:$

As we know that,

$\dagger \: { \boxed{ \blue{ \tt{Amount = Principal + Interest }}}}$

[ Put the values ]

$\longrightarrow \: \tt \: 10370 \: = P \: + \frac{11P}{50} \\ \\ \longrightarrow \: \tt \: 10370 \: = \tt \frac{50P + 11P}{50} \\ \\ \longrightarrow \: \tt 10370 \: \times 50 \: = 61P \\ \\ \longrightarrow \tt \: 518500 \: = 61P \\ \\ \longrightarrow \tt P \: = \frac{ \cancel{518500}}{ \cancel{61}} \\ \\ \longrightarrow \: { \purple{{ \tt{P \: = Rs.8500}}}}$

Now,

$\tt \longrightarrow \: S. I = \: \frac{ 85\cancel{00} × 11 × 3}{1\cancel{00}} \\ \tt \: \\ \longrightarrow \: \tt S. I = \: 85 \: \times 33 \\ \\ \tt \longrightarrow \:{ \blue{ S. I =Rs. 2805}}$

Hence, Amount after 3 years will be,

$\tt \longrightarrow \: Amount = 8500 + 2805 \\ \\ \tt \longrightarrow \:{ \red{ Amount = \: Rs.11305}}$

Therefore, the amount after 3 Years will be Rs.11305.