A sum of money was distributed among boys in the class. Had there been 10 boys more, each would have received a rupee less and had there been is less, each would have received ₹3 more. Find sum of money distributed and number of boys.
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Let the sum of rupee be x and no of boys be y then each boy get x/y now if the no of boys increased by 10 each boy get x/(y+10) = (x/y)-1 => x/(y+10) = (x-y)/y ............,.(1) now case 2nd if no of boys decrease by 15 each boy get x/(y-15)= (x/y) +3 => x/(y-15) = (x+3y)/y ...........(2) solve the equations and get the answer
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