Math, asked by arhaanyaser8354, 1 year ago

a sum of rs 20706 is distributed amongst a b and c. a gets 10/123 of what b and c got together and c gets 1/10 of what a and b got together c's share is (approx)?

Answers

Answered by agaue
9

Total amount distributed among a,b and c = Rs 20706

Or a+b+c=20706

Given : a gets  \frac{10}{123}  of what b and c got together.

Or a= \frac{10}{123} (b+c)

Also given c gets  \frac{1}{10}  of what a and b got together

Or c= \frac{1}{10} (a+b)

Since a+b+c=20706

Subtracting c both sides a+b=20706-c

Substituting a+b value in c= \frac{1}{10} (a+b)

c= \frac{1}{10} (20706-c)

Multiplying both sides by 10

10c=20706-c

Adding c both sides

11c=20706

c=1882.36

C 's share is approximately Rs .1882.


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