Question

A sum of rs.2387 is divided into three parts in such a way that one fifth of the first part, one half of the second part and one fourth the third part are equal. Find the sum of five times the first part, three times the second part and four times the third part (in rupees).

Answer 1

Answer:

lets assume 3 parts of amount are x,y,z

x+y+z=2379

SI for x= x*5*2/100=> x/10

Total amount after 2 years - x+(x/10)= 11x/10 ------------(1)

SI for y= y*5*3/100=> 15y/100

Total amount after 3 years - y+(15y/100) = 115y/100 -------(2)

SI for z= z*5*4/100=> z/5

Total amount after 4 years - z+(z/5) = 6z/5 ---------------(3)

As per the conditions "3 parts amounts after 2, 3 and 4 years respectively may be equal" (1) = (2) = (3)

based on the above condition and x+y+z=2379, we can get x= 828, y= 792 and z= 759

So answer is Rs.828

Step-by-step explanation:

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