a sum of rs.3.75 was paid in 25p, 0p, 5p coins. the number of 10p coins was four times the number of 25p coins and twice the number of 5p coins the number of 10 p coin is
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Answer:
Let the number of 10 paisa coins be x, number of 25 paisa coin=
4
x
Number of 5 paisa coin=
2
x
According to the given problem,
⇒
100
10x
+
4
x
×
100
25
+
2
x
×
100
5
=3.75
⇒
100
10x
+
400
25x
+
200
5x
=
100
375
⇒
400
40x
+
400
25x
+
400
10x
=
100
375
⇒
400
40x+25x+10x
=
100
375
⇒
4
75x
=
1
375
∴x=
75
1500
=20
Number of 10 paisa coins=20
Number of 25 paisa coins=5
Number of 5 paisa coins=10
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