Question

A sum of rs 3000 is distributed amongst a, b, and

c. a gets 2/3 of what b and c got together and c gets 1/3 of what a and b got together, c's share is?

Answer 1

We can take A + B + C = 3000 whereas A = (2/3)(B + C) and C = (1/2)(A + B).

When we enter the values, we can get A + B - 2C = 0.  

We can get 3C is 3000, so the value of C is 1000.  We can get A + B = 2000, 3A - 2B = 2000 and 2A + 2B = 4000.

After that, we can get 5A = 6000. Here are A is 1200 and B is 800.

Answer 2

Concept Introduction:-

It may resemble a word or a number that represents the numerical value of the quantity. It could resemble a word or a number that represents the numerical value of the quantity. It could look like a word or a number that indicates the quantity's numerical value. It could have the appearance of a word or a number that denotes the quantity's numerical value.

Given Information:-

We have been given that A sum of rs $3000$ is distributed amongst $a, b,$and $c$. $a$ gets $2/3$ of what $b$ and $c$ got together and $c$ gets $1/3$

To Find:-

We have to find that $a$ and  $b$ got together, $c$'s share is

Solution:-

According to the problem

We can take $a +b+c= 3000$

Whereas $a = (2/3)(b+c)$ and $c = (1/2)(a+b)$.

When we enter the values, we can get $a+b-2c= 0$.  

We can get $3C$ is $3000$, so the value of $c$ is $1000$.  We can get $a + b = 2000$, $3a - 2b = 2000$ and $2a + 2b = 4000$.

After that, we can get $5a = 6000$. Here are $a$ is $1200$and $b$ is $800$.

Final Answer:-

The correct answer is that  $a$ is $1200$ and $b$ is $800$, the value of $c$ is $1000$.

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