Question

A Sum of Rs.3000 is to be given in the form of 63 prizes . if the prize money is either Rs.100 or Rs.25 .find the number of prize of each type. ​

Answer 1

Answer:

the answer is in the above picture

x= no of prize of 100/-

y= no of prize of 25/-

100x+25y=3000

x+y=63

100×+25y=3000

(x+y)×100=63×100

100x+100y=6300

100x+100y=6300-100x+25y=3000

75y =3300

y =3300/75

=44

x+y =63

x+44=63

x =63-44=19

x= no of prize of 100/- =19

y= no of prize of 25/- =44

Answer 2

Answer:

Rs.25=44,Rs.100=19

Step-by-step explanation:

Let, the no. of Rs.25 be x and Rs.100 be (63-x)

value of Rs.25=(25*x)=25x

value of Rs.100=100(63-x)

A/Q-

25x+6300-100x=3000

-75x=3000-6300

-75x=-3300

75x=3300

x=44

(63-x)=19