A Sum of rs 3000 is to be given in the form of 63 prizes. if the prize money is either rs 100 or rs 25 find the number of prizes of each type.
Answers
Answered by
612
Let the number of prizes of money 100 be x, and the number of prizes of cost 25 be y ;
x+y = 63
y = 63-x -------(1)
100x+25y = 3000
4x+y = 120
y = 120-4x ------(2)
63-x = 120-4x
4x-x = 120-63
3x = 57
x = 19
y = 63-x = 63-19
y = 44
Hence the number of prizes of cost 100 each are 19 while other type of prizes are 44
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x+y = 63
y = 63-x -------(1)
100x+25y = 3000
4x+y = 120
y = 120-4x ------(2)
63-x = 120-4x
4x-x = 120-63
3x = 57
x = 19
y = 63-x = 63-19
y = 44
Hence the number of prizes of cost 100 each are 19 while other type of prizes are 44
____________________
Answered by
208
according to the question
total amount = 3000rs
total no. of prizes = 63
Let the no. of prizes for 100 rs = X
so , the no. of prizes for 25 rs. =y
X + Y =63 ................. eq 1
100x+25y =3000........eq2
y= 63-x ................. eq 3
substituting eq 3 in eq 2 , we get
100x +25( 63-x) = 3000
100x. + 1575 -25x = 3000
75x = 3000-1575
75x= 1425
X = 3000/1425
X=19...........eq 4
substituting eq 4 in eq 3
y=63-x
y=63-19
y=44
Therefore, the prizes are 19,44
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