Question

A sum of Rs. 650 is divided between A and B in such a manner that in every 100 rupees A gets 30 rupees more than B. How much does B get?​

Answer 1

Given that:

• A sum of Rs. 650 is divided between A and B in such a manner that in every 100 rupees A gets 30 rupees more than B.

To Find:

• How much does B get?

In every

• 100 rupees, A gets 30 rupees more than B.
• 1 rupee, A gets 30/100 rupees more than B.
• 650 rupees, A gets (30 × 650)/100 rupees more than B.

i.e., A gets 195 rupees more than B.

Let us assume:

• B's share be x
• A's share = x + 195

Finding the share of A and B:

According to the question.

↣ x + 195 + x = 650

↣ 2x + 195 = 650

↣ 2x = 650 - 195

↣ 2x = 455

↣ x = 455/2

↣ x = 227.50

Hence,

• B gets 227.50 rupees.

Answer 2

Given :-

A sum of Rs. 650 is divided between A and B in such a manner that in every 100 rupees A gets 30 rupees more than B.

To Find :-

How much B get

Solution :-

A + B = 100

It is given than in 100 rupees A got 30 rupees more than b

Then,

A = 30 + B (i)

Putting the value of A in above equation

30 + B + B  = 100

2B + 30 = 100

2B = 100 - 30

2B = 70

B = 70/2

B = 35

Now,

Using 1 to find value of A

A = 30 + 35

A = 65

Dividing both A and B to get ratio between these two

A/B = 65/35

A/B = 13/7

A : B = 13 : 7

Let the rati be 13y and 7y

A + B = 650

13y + 7y = 650

20y = 650

y = 650/20

y = 65/2

y = 32.5

Now,

Amount of B = 7y

Amount of B = 7(32.5)

Amount of B = 227.5