A sum of Rs.750 was divided between A and B in the ratio 23 : 27 . What percentage does each get?
Answers
Answered by
4
let the ratio sum=23x,27x
23x+27x=750
50x=750
x=750/50
x=15
A gets=23×15=345
B gets=27×15=405
what percentage A get of 750
=750×x\100=345
x=345×100/750
x=46%
A gets 46%
B gets = 100-46=54
B gets 54% of 750
23x+27x=750
50x=750
x=750/50
x=15
A gets=23×15=345
B gets=27×15=405
what percentage A get of 750
=750×x\100=345
x=345×100/750
x=46%
A gets 46%
B gets = 100-46=54
B gets 54% of 750
Answered by
3
Let money they got be 23x and 27x
A. T. Q
23x+27x= 750
50x= 750
x=750/50
x=15
So 1st got:- 23*15= 345
2nd got:- 27*15 =405
Percentage of 1st :- 345/750*100
= 46%
Percentage of 2nd:- 405/750*100
=56%
A. T. Q
23x+27x= 750
50x= 750
x=750/50
x=15
So 1st got:- 23*15= 345
2nd got:- 27*15 =405
Percentage of 1st :- 345/750*100
= 46%
Percentage of 2nd:- 405/750*100
=56%
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