in a simultaneous throw a pair of dice find the probability of getting a doublet
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21
Total number of possible outcomes when a pair of dice is thrown = 36
Sample space = (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)
= 6
Probability (getting doublet) = 6/36
= 1/6
Sample space = (1,1) (2,2) (3,3) (4,4) (5,5) (6,6)
= 6
Probability (getting doublet) = 6/36
= 1/6
abarajith87691:
hii
Answered by
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Heya !!!
When two simultaneous pair of dice is thrown then the number of duplet are
(1 ,1) ,( 2 , 2) , (3 , 3) , (4 , 4) , (5 , 5) and (6 ,6)
Possible outcomes = 36
And,
Favourable outcomes = 6
Therefore,
P ( Getting a duplet ) = Favourable outcomes/Possible outcomes = 6/36 = 1/6.
HOPE IT WILL HELP YOU..... :-)
When two simultaneous pair of dice is thrown then the number of duplet are
(1 ,1) ,( 2 , 2) , (3 , 3) , (4 , 4) , (5 , 5) and (6 ,6)
Possible outcomes = 36
And,
Favourable outcomes = 6
Therefore,
P ( Getting a duplet ) = Favourable outcomes/Possible outcomes = 6/36 = 1/6.
HOPE IT WILL HELP YOU..... :-)
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