Question

A sum of rs 800 is in the form of denominations of rs 10 and rs 20. If the total number of notes be 50,find the number of notes of each type.
Chapter is linear equations in one variable, so please don't use two variables.

Answer 1

Let there be X notes of Rs 10.
Total number of notes = 50.
∴ Number of notes of Rs 20 = (50 – x)
Total sum of money = Rs 800
∴ 10x+ 20 (50 – x) = 800
⇒ 10x+ 1000 – 20x = 800
⇒– 10x = 800 – 1000
⇒ – 10x= – 200
⇒x= 20
∴ 50 – x = 50 – 20= 30
So, there are 20 notes of Rs 10 and 30 notes of Rs 20.

Answer 2

Answer:

No. of notes of Rs.10 is 20 and no. of notes of Rs.20 is 30

Step-by-step explanation:

let x be the no. of notes of Rs.10

We are given that the total number of notes be 50

So, no. of notes of Rs.20 = 50-x

Value of x notes of Rs.10 = 10x

Values of (50-x) notes of Rs.20 = 20(50-x)

Now we are given that the total sum of money is Rs.800

So, $10x+20(50-x) =800$

$10x+1000-20x =800$

$1000-10x =800$

$200=10x$

$x=20$

So, no. of notes of Rs.10 is 20

No. of notes of Rs. 20 = 50-x =50-20 = 30

Hence no. of notes of Rs.10 is 20 and no. of notes of Rs.20 is 30