a sum of rupees 50,000 bought at the rate of interest 20% for 3 years
annually find its compound interest
Answers
Answered by
0
Answer:
According to given sum,
principle=50,000
Time=3 years
Rate per annum=12%
compound \: interest = p {(1 + \frac{r}{100} })^{3}compoundinterest=p(1+
100
r
)
3
= 50000 {(1 + \frac{12}{100} })^{3}=50000(1+
100
12
)
3
= 50000 {( \frac{28}{25} })^{3}=50000(
25
28
)
3
=70,246.4
Answered by
0
Step-by-step explanation:
is given that
Principal (P) = 50000
Rate of interest (r) = 8% p.a. = 4% semi-annually
Period (n)= 1
2
1
years = 3 semi-annually
We know that
Amount = P(1+r/100)
n
Substituting the values
= 50000(1+4/100)
3
By further calculation
= 50000(26/25)
3
= 50000×26/25×26/25×26/25
= 56243.20
Here
Compound interest = A - P
Substituting the values
= 56243.20−50000
= 6243.20
Similar questions