a sum of rupees 500 is in the form of denominations of rupees 5 and rupees 10 if the total number of notes is 90 find the number of notes of each type
Answers
Answered by
2
let the common fraction be x
then
5x+10y= 500
and
x+y=90
solve the equations and u will have ur answer
hope this helps u
then
5x+10y= 500
and
x+y=90
solve the equations and u will have ur answer
hope this helps u
Answered by
4
Let x be the number of notes of denomination Rs5
Let y be the number of notes of denomination Rs10
we know that the total amount is Rs500 which means 5 times the number of notes of denom Rs5 + 10 times the number of notes of denomination Rs 10 equals 500
ie. 5x+10y=500
Also total number of notes is 90 ie x+y=90
hence x=90-y
5*(90-y)+10y=500
450-5y+10y=500
5y=500-450
5y=50
y=50/5
y=10
x=90-y=90-10=80
hence 10 notes of Rs10 and 80 notes of Rs5
Let y be the number of notes of denomination Rs10
we know that the total amount is Rs500 which means 5 times the number of notes of denom Rs5 + 10 times the number of notes of denomination Rs 10 equals 500
ie. 5x+10y=500
Also total number of notes is 90 ie x+y=90
hence x=90-y
5*(90-y)+10y=500
450-5y+10y=500
5y=500-450
5y=50
y=50/5
y=10
x=90-y=90-10=80
hence 10 notes of Rs10 and 80 notes of Rs5
flower99:
thanks
Similar questions