Question

A sum of three consecutive odd numbers is 63.Find the numbers

Answer 1

Hello!

Let the numbers be x, x+2 and x+4.
As every consecutive odd number differ by two.

Now,
x+x+2+x+4 = 63
3x + 6 = 63
3x = 63 - 6
3x = 57
x = 57/3
x = 19

So the numbers are,
x = 19
x + 2 = 19 +2 = 21
x + 4 = 19 + 4 = 23

Hope it helps!

Answer 2

Here is your solution

Let,
The first odd integer be:x

Then the second odd integer is:-
x+2

Then the third odd integer is:-
x+2+2=x+4

Sum of three consecutive odd numbers =63

A/q

(x)+(x+2)+(x+4)=63
3x+6=63
3x=63-6
3x=57
x=19
now

The first integer is: x=19

the second integer is: x+2=19+2 = 21

the third integer is: x+4=19+4=23

Hope it helps you