A sum of two digit number and the number obtained on revising the digit is 99. if the number obtained on revising the digit is 9 more than the original number. find the number?
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Let us assume, x and y are the two digits of the two-digit number
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x
Given:
10x + y + 10y + x = 99
11x + 11y = 99
x + y = 9 -------------1
Also given:
10y + x = 10x + y + 9
9y - 9x = 9
y - x = 1 -----------------2
Adding equation 1 and equation 2
2y = 10
y = 5
Therefore, x = 9 - y = 9 - 5 = 4
Therefore, the two digit number = 10x + y = 10*4 + 5 = 45
Answer - The number is 45
Therefore, the two-digit number = 10x + y and the reversed number = 10y + x
Given:
10x + y + 10y + x = 99
11x + 11y = 99
x + y = 9 -------------1
Also given:
10y + x = 10x + y + 9
9y - 9x = 9
y - x = 1 -----------------2
Adding equation 1 and equation 2
2y = 10
y = 5
Therefore, x = 9 - y = 9 - 5 = 4
Therefore, the two digit number = 10x + y = 10*4 + 5 = 45
Answer - The number is 45
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